npub1ar…akg37

"b18ba1e3a6a1da1283ab49ac491b4cac78a9871627acd23f074598cfdea9e9ea3ae5c47c86afe5c5d4f003cdd591354687c0b7beb47b17455e957dc777c1337d"

Last Notes

2023-05-11 17:17:18 UTC

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The screenshots are from my own client. Channels are just kind 40 / 42 events.

2023-04-21 15:12:55 UTC

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Is it used for communication?

2023-04-13 02:53:40 UTC

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Are you vegan?

2023-04-13 02:45:20 UTC

I just found these messages in a channel on Nostr. I hope he's doing alright...
https://nostr.build/i/nostr.build_02c131b067e422c0bf09c96d9066dd1c95f6b76ef659d7f04124dd6444db3d5a.png
https://nostr.build/i/nostr.build_5b9039ae1586db5ad40a57fd66ffc53dfceb5c62b4f7662a8b27230ed54121a8.png

2023-04-11 12:33:50 UTC

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Here is ChatGPTs answer
What would be a simplified formula for a sequence like this:
n*10^0+n*10^1+n*10^2+n*10^3…
The given sequence can be written in sigma notation as:
∑(n*10^k) for k=0 to infinity
where ∑ represents the summation operator and k is the index variable that ranges from 0 to infinity.
Using the formula for the sum of an infinite geometric series, we can simplify the above expression as:
∑(n*10^k) for k=0 to infinity = n/(1-10) * ∑(10^k) for k=0 to infinity
= n/-9 * (1/(1-10))
= n/9
Therefore, the simplified formula for the given sequence is n/9.

2023-03-01 16:08:57 UTC

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It's simple: via NIP05. Alex Jones would spread around his NIP05 address, and the client would automatically fetch the data from the relay list in the NIP05 json file.

2023-02-02 18:23:24 UTC

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This is why we need topic-related relays like on Matrix. No data duplication across ten different relays. This isn't a blockchain.