You can't really take an existing secret key and "join" with that key being your secret share in FROST. Your secret polynomial is only an input to key generation and not what you sign with.
Undertaking key generation with the other parties will give you a secret share that depends on their (and your own) contributions
nick
npub1j8…g26k2
2024-02-11 14:36:58 UTC
in reply to nevent1q…ccx3
Author Public Key
npub1j8d6h8mzvc8f2fvysrf09nlkmn7m2ylj32zl5na4tm5e8fd5dqysrg26k2Published at
2024-02-11 14:36:58 UTCEvent JSON
{
"id": "867c8cdccff4cec9626089b0a96592f6975290d5cf8648acf7ba9e63f1456631",
"pubkey": "91dbab9f62660e95258480d2f2cff6dcfdb513f28a85fa4fb55ee993a5b46809",
"created_at": 1707662218,
"kind": 1,
"tags": [
[
"e",
"a4e04255b4c5aa77d5cf587d4652126c47d068e3800d88ca425d911b433f9a42",
"",
"root"
],
[
"e",
"10477fdf13737da3c88d7bb99027e3e7107d7971ca6c46e344328471a53f3e8e",
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"reply"
],
[
"p",
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],
[
"p",
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[
"p",
"d3d74124ddfb5bdc61b8f18d17c3335bbb4f8c71182a35ee27314a49a4eb7b1d"
]
],
"content": "You can't really take an existing secret key and \"join\" with that key being your secret share in FROST. Your secret polynomial is only an input to key generation and not what you sign with.\n\nUndertaking key generation with the other parties will give you a secret share that depends on their (and your own) contributions",
"sig": "c9cd5233cf78ee7b284c88343deb550b7834b1b510ca37eb17256a26d7073ccbb529857a01ccd10022977a4b73948422db0498fbcba218e67401264ec71f757d"
}