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2025-01-24 09:42:17 UTC

Greg Egan on Nostr: It might be fun to work through an example of quantum "teleportation", to see why you ...

It might be fun to work through an example of quantum "teleportation", to see why you need a classical message as well as an entangled pair. (The following is adapted from "Quantum Theory: Concepts and Methods" by Asher Peres.)

Let A and B be two spin-(1/2) particles in the entangled state:

\[ \psi_{AB} = (u_A d_B - d_A u_B) / \sqrt{2}\]

where \(\{u_P, d_P\}\) are the spin-up and spin-down states for particle P.

Let X be a spin-(1/2) particle in an unknown state:

\[$\psi_X = \alpha u_X + \beta d_X\]

giving a total state for the three particles:

\[\psi_{XAB} = (\alpha u_X + \beta d_X) (u_A d_B - d_A u_B) / \sqrt{2}\]

or, expanding this out:

\[\psi_{XAB} = (\alpha u_X u_A d_B - \alpha u_X d_A u_B +
\beta d_X u_A d_B - \beta d_X d_A u_B) / \sqrt{2}\]

Suppose Alice has particle A of the entangled pair, along with particle X that she wants to "teleport" to Bob, while Bob has particle B.

Alice performs a measurement on X and A that resolves
their state into one of the following four orthonormal states:

\[e_{00} = (u_X d_A - d_X u_A) / \sqrt{2}\]

\[$e_{01} = (u_X d_A + d_X u_A) / \sqrt{2}\]

\[e_{10} = (u_X u_A - d_X d_A) / \sqrt{2}\]

\[e_{11} = (u_X u_A + d_X d_A) / \sqrt{2}\]

Given the result of that measurement, if Bob performs the correct operation
on particle B for each possible outcome, that will guarantee that after he's done so, any subsequent measurements on B's spin degree of freedom will be identical to those you'd get for the original state of particle X.