Bartosz Milewski on Nostr: It's possible to define a "proportional product" of two objects using copowers. Given ...
It's possible to define a "proportional product" of two objects using copowers. Given two sets \(A\) and \(B\) we can define \(A \cdot a \times B \cdot b\) using the adjunction:
\[ C(A \cdot a \times B \cdot b, c) \cong Set (A, C(a, c)) \times Set(B, C(b, c))\]
I thought of this trying to work out a category theory of French sauces. You need such a product when you mix ingredients in different proportions. I think of a sauce as a functor.
Published at
2025-02-22 13:40:02 UTCEvent JSON
{
"id": "caf79b038d31b790ba29e3602019e3872a157d5767fdd79968fe8e19d4e142dd",
"pubkey": "47d069b9227182c947fa6974c32d7cdf8764f5916ef0e6d88011720b2cf1db53",
"created_at": 1740231602,
"kind": 1,
"tags": [
[
"proxy",
"https://mathstodon.xyz/@BartoszMilewski/114047818324749030",
"web"
],
[
"proxy",
"https://mathstodon.xyz/users/BartoszMilewski/statuses/114047818324749030",
"activitypub"
],
[
"L",
"pink.momostr"
],
[
"l",
"pink.momostr.activitypub:https://mathstodon.xyz/users/BartoszMilewski/statuses/114047818324749030",
"pink.momostr"
],
[
"-"
]
],
"content": "It's possible to define a \"proportional product\" of two objects using copowers. Given two sets \\(A\\) and \\(B\\) we can define \\(A \\cdot a \\times B \\cdot b\\) using the adjunction:\n\\[ C(A \\cdot a \\times B \\cdot b, c) \\cong Set (A, C(a, c)) \\times Set(B, C(b, c))\\]\n\nI thought of this trying to work out a category theory of French sauces. You need such a product when you mix ingredients in different proportions. I think of a sauce as a functor.",
"sig": "f0c647ffeda2004d51f4b52ef8369a96daed8d5d4609957577d09931f1b2348416083f574a0dc189a54fc376dfeac7cd0467b85b8d1c3e0aecb6d8404fed397a"
}