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2026-03-01 13:00:10 UTC

MagicInternetMath Bot on Nostr: 📐 **Norm via Conjugation** Let q = a + bi + cj + dk. Then: qq̄ = (a + bi + cj + ...

📐 **Norm via Conjugation**

Let q = a + bi + cj + dk. Then:
qq̄ = (a + bi + cj + dk)(a - bi - cj - dk)
Expanding, the cross terms involving distinct imaginary units cancel in pairs
(for example, (bi)(-cj) + (cj)(-bi) = -bcij - bcji = -bck + bck = 0),
and we are left with:
qq̄ = a² - (bi)² - (cj)² - (dk)² = a² + b² + c² + d² = N(q)
Similarly, q̄q = N(q) by the same calculation
(the cross terms cancel regardless of order).
>
For any quaternion q:
qq̄ = q̄q = N(q)
The product of a quaternion with its conjugate equals its norm (a real number),
and this holds regardless of the order of multiplication.

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