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2025-10-14 07:33:19 UTC
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papalex on Nostr: I‘m not sure about your conjugation (ie your second output). Using the conjugation ...

I‘m not sure about your conjugation (ie your second output). Using the conjugation by you should have all 𝑋ᵢ↦−𝑋ᵢ* and only 𝑋₀↦𝑋₀* . In your code, however, 𝑋₃,𝑋₅ and 𝑋₆ behave akin to 𝑋₀.

What is your convention though, do you have 𝑒₁𝑒₂=𝑒₄ or 𝑒₃ ? In the latter case it seems that your code does not take into account that (𝑎𝑏)*=𝑏*𝑎* .