correct me if I'm wrong, but 2412 MHz is the frequency of the alternating current. Having a cable doesn't change the frequency of the alternating current, it just makes the circuit longer.
The length of the antenna is required for the right wave to be able to escape the circuit and travel through the air.
Assuming that the cable can be modeled as an extension of the antenna (in a dipole antenna this is clearly not the case). If you send a 2412 MHz signal through the wire, you would still get 2412MHz radio waves, the only difference is that your new antenna (antenna + cable) is worse at transmitting it.
I am just an amateur SDR user, so I might have made many mistakes. Just answering from intuition.
Qmodo
npub1xz…wqx57
2024-09-05 00:28:18
in reply to nevent1q…64g9
Author Public Key
npub1xzdd0zcpfm7usa8735jj7pjynljv4rdcjuv93hal65df44t8pl2suwqx57Published at
2024-09-05 00:28:18Event JSON
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"content": "correct me if I'm wrong, but 2412 MHz is the frequency of the alternating current. Having a cable doesn't change the frequency of the alternating current, it just makes the circuit longer.\n\nThe length of the antenna is required for the right wave to be able to escape the circuit and travel through the air.\n\nAssuming that the cable can be modeled as an extension of the antenna (in a dipole antenna this is clearly not the case). If you send a 2412 MHz signal through the wire, you would still get 2412MHz radio waves, the only difference is that your new antenna (antenna + cable) is worse at transmitting it.\n\nI am just an amateur SDR user, so I might have made many mistakes. Just answering from intuition.",
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