Yes, I'm also used to up/down summation-- I had to force myself to lower them all ;-).
A quick check for this formula is to realize that both sides must be anti-symmetric in free indices, and that \(\epsilon_{1 2 3}\}\) is equal to one.
Bartosz Milewski
npub1gl…xtqzy
2025-05-20 12:22:36 UTC
in reply to nevent1q…842d
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2025-05-20 12:22:36 UTCEvent JSON
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