Event JSON
{
"id": "7589b6bf863922ae8df12454fedd36462af2eefb8cdb654d00c5d02d08baca26",
"pubkey": "d5a443061b20e85fc2fde6bdb03e5f578aee0539008fe22a4a6c93e3c0ba2608",
"created_at": 1746200418,
"kind": 1,
"tags": [
[
"t",
"testandmeasurement"
],
[
"t",
"stem"
],
[
"t",
"laserfun"
],
[
"imeta",
"url https://files.techhub.social/media_attachments/files/114/438/981/626/365/678/original/6c6a96f46296e49f.mp4",
"m video/mp4"
],
[
"t",
"engineer"
],
[
"proxy",
"https://techhub.social/@oz1lqo/114438990632722710",
"web"
],
[
"t",
"physics"
],
[
"proxy",
"https://techhub.social/users/oz1lqo/statuses/114438990632722710",
"activitypub"
],
[
"L",
"pink.momostr"
],
[
"l",
"pink.momostr.activitypub:https://techhub.social/users/oz1lqo/statuses/114438990632722710",
"pink.momostr"
],
[
"-"
]
],
"content": "As light enters a more dense medium, it well bend because of the speed reduction in that media. A bit like if your right wheel enters the gravel next to the road, the car wants to go there.\n\nNow here comes the magic: \n1) My sugar solution is a beautiful gradient: more dense towards the bottom, more watery towards the surface. This causes the light to bend in a nice curve, finally hitting the bottom.\n2) I managed to find a balance where I have a nice density gradient and none or little sugar on the bottom. So now the bottom becomes a mirror because of the water and acrylic boundary. \nThe light will now reflect from the bottom, starting a new curve. \nThis will go on for the entire length of the container, or until I run out of light (it spreads, disperses, along the way). You can see I barely got started on the second jump. \n \nOh and the really cool thing: occasionally radio signals do the same, if the atmospheric conditions are just right 🙂\n\n#stem #laserfun #engineer #testandmeasurement #physics\nhttps://files.techhub.social/media_attachments/files/114/438/981/626/365/678/original/6c6a96f46296e49f.mp4\n",
"sig": "e6a295d0d0b5f8e2e47a5f5b6489043cb99d2bfc76a966c7c89d1a4141992661c380be0ddf2c726961a20745eb4a83c7caf45d3a4d10a09cd6698c1b0a95f190"
}